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1.A ball is thrown downward, with an initial speed of 6.34 m/s, from a height of 45.2 m. After what time interval does the ball strike the ground?


2. A dog searching for a bone walks 4.31 m south, then runs 8.93 m at an angle 22.0 north of east, and finally walks 10.0 m west. Find the magnitude of the dog's resultant displacement vector.

3.A dog searching for a bone walks 2.87 m south, then runs 22.5 m at an angle 30.5 north of east, and finally walks 5.91 m west. Find the direction of the dog's resultant displacement vector. Give your answer as an angle in degrees, with the angle measured counterclockwise from the line pointing straight East (North is 90, while South is -90).

2007-09-05 17:44:59 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

1.
Solve
45.2 m = 0.5 * 9.81 m/s² * t² + 6.34 m/s * t
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2.
√ [(-4.31 + 8.93 * sin 22°)² + (8.93 * cos 22° - 10)²]
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3.
arctg [(-2.87 + 22.5 * sin 30.5°) / (22.5 * cos 30.5° - 5.91)]
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2007-09-05 17:59:54 · answer #1 · answered by oregfiu 7 · 1 0

you mustn't get puzzled once you spot them. they're all suitable in case you be attentive to the right physics recommendations. evaluation Newtons 2d regulation and how tension pertains to a ability. the reason i choose physics over the different sciences. Is which you do not could desire to alot memorize equations and exceptions. many circumstances you may derive necessary equations from undemanding ones. additionally, basically save doing issues. After fixing sufficient issues, some equations grow to be 2d natures and don't require hours of flash enjoying cards.

2016-10-18 02:34:54 · answer #2 · answered by Anonymous · 0 0

1st one: s = 1/2at^2 +vit

45.2 = 1/2(9.8)t^2 + 6.34t

4.9t^2 + 6.34t -45.2 = 0

using quadratic formula

t = (-6.34 +sqrt(40.1956 +885.92))/9.8

t = approximately 2.46 seconds


2. and 3. are much easier with diagrams, try and find someone to show you them

2007-09-05 18:07:38 · answer #3 · answered by Anonymous · 0 0

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