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Hi guys. I'm just having difficulty with this one problem. There were two, I answered the first one which was:

1. Calculate how much 95% ethyl alcohol will be required to dissolve 0.3g of sulfanilamide at 78 ' C.

I got 300 mg sulfanilamide ( 1ml / 210mg SAmide) = 1.42867143ml.

Now it is asking:

2. Using the volume of solvent calculated in Step 1, calculate how much sulfanilamide will remain dissolved in the mother liquor after the mixture is cooled to 0 ' C.

I know the solubility of sulfanilamide at 0 ' C is 14 mg/ml but I don't know where to go after this. Please help me understand this problem! Any help will be much appreciated. We are doing a Semimicroscale Crystallization lab using Erlenmeyer Flasks and a Hirsch Funnel. Thank you all in advance!

2007-09-05 17:10:27 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

I do not know previously the solubility of sulfanilamide in 95% ethyl alcohol. Let us accept the solubility you quoted here.
300/210 = 1.428571428.. ≈ 1.43 (ml)
at 0C, the amount of sulfanilamide remains in the solution is:
14*(300/210) = 20 (mg), since you only have 1.43ml solution.
The volume of the solution will change a little by cooling from 78C to 0C. You may also consider this volume change if you have data.

2007-09-07 12:44:38 · answer #1 · answered by Hahaha 7 · 1 0

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RE:
Easy question for my pre-lab in Organic Chemistry?
Hi guys. I'm just having difficulty with this one problem. There were two, I answered the first one which was:

1. Calculate how much 95% ethyl alcohol will be required to dissolve 0.3g of sulfanilamide at 78 ' C.

I got 300 mg sulfanilamide ( 1ml / 210mg SAmide) = 1.42867143ml....

2015-08-06 06:38:28 · answer #2 · answered by Anonymous · 0 1

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2016-04-10 11:47:33 · answer #3 · answered by Anonymous · 0 2

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2016-03-15 22:40:34 · answer #4 · answered by Amber 4 · 0 1

Sulfanilamide Solubility

2016-11-04 11:49:12 · answer #5 · answered by ? 4 · 0 1

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