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using the reference angle to find the exact value of each expression . . . without calculator

a) csc (7pi)/4, I said it's coterminal with (pi/4) so csc (7pi)/4 = csc (-2pi +(pi/4)) so csc = (pi/4) = sq root 2

did I do this right??

and how would i do this one??

b) cos (2pi) / 3


and c) sec (11pi)/4

sorry my book does a crappy job explaining this so I'm just having a hard time, if you could please help me, I would appreciate it! THANKS

2007-09-05 17:08:42 · 3 answers · asked by rickyricardoiscool 1 in Science & Mathematics Mathematics

3 answers

There's an easier way to do that.

csc(x)=1/sin(x)

since sin(7pi/4) is -root(2)/2
just take 1/-root(2)/2
2/-root(2)=-root(2)

cos(pi/3)=1/2
2pi/3 would just make it negative

11pi/4 is the same as 3pi/4
cos(3pi/4)=-root(2)/2
1/-root(2)/2=-root(2)

2007-09-05 17:25:31 · answer #1 · answered by www 2 · 0 0

Yes, the way to do this is correct except, you have to know which quad the angle is in and for 7pi/4, it is in quad 4, so sin and csc are negative.

I like to do it in degrees
2pi/3 = 120 cos 120 = cos 60 = rt(3)2
cos in quad 2 is also negative = -rt(3)/2

11pi/4 = 495
sec 495 = sec 135 = sec 45
in quad 2, sec is negative = -rt(2)

2007-09-06 00:20:25 · answer #2 · answered by norman 7 · 0 0

omg I wish knew..I hate math..but I hope someone helps you!

2007-09-06 00:15:02 · answer #3 · answered by Anonymous · 0 0

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