someone help me with this chemistry problem?

Question

You have a 200.0 mL graduated cylinder containing 56.9 mL of water. A piece of metal with a density of 9.30 g/cm3 weighing 190.90 g is placed in the cylinder. What is the reading on the cylinder after the metal has been added? Enter your answer with the correct number of significant figures.

Answer 1

first, list of all information:
graduated cylinder = 200.0 mL----4 significant fig.
volume of water = 56.9 mL ---- 3 significant fig.
Density of metal= 9.30 g/cm3 --- 3 significant fig.
weight of metal = 190.90 g ---- 5 significant fig.

question: what is the final volume in the cylinder?

We know that: density = g/cm3
weight = g
by looking the units, we should know directly that we can get the volume of the metal by canceling the gram and get the cm3...
actually there is also the formula for density:
density = weight / volume ---- g/cm3
so volume= density/weight ----g/cm3 : g

then: volume of metal= 9.30 g/cm3 : 190.90 g= 0.04871cm3
= 0.04871mL
(note: 1 cm3 = 1 mL)

the reading after the metal added:
before the metal added: we already have 56.9 mL
so if the metal added:the volume will increase as much as the volume of metal which is:56.9mL+0.04871mL= 56.9487mL

to count the significant figure:
because we have 200.0 mL in the graduated cylinder, nad we will read through this tools, automatically our answer's significant figure will be based on this number which has 4 sig. fig.

so, our last answer will be 56.95 mL...
(it is rounded to the next number because of "8" behind the "4")

Answer 2

Divide 190.9 by 9.3. That will give you the cc (or mL) of the metal. Add that to the 56.9 mL of water. Answers should be significant to three places.

Answer 3

220.5 mL