Help me on this algebra math problem!!!?

Question

Find the discriminant and state the nature the roots: 3x^2-5x+3=0

First person to show the work and answer i'll mark best answer

thanks

I already have chosen the best answer..I just now have to wait for the time limit..Thanks anyways

Answer 1

for a quadratic equation in the form:
ax^2+bx+c=0
the roots are given by
x = [-b +/- sqrt(b^2-4ac)]/(2a)

the discriminant is b^2-4ac

for the case at hand, this evaluates to
(-5)^2-4(3)(3) = 25-36 = -9

because this is negative, the roots will
be complex conjugates

Answer 2

The discriminant is the sqrt(b2-4ac) term in the general solution to the quadratic equation.

Here, the value is sqrt(25-4*3*3) or sqrt(-11)
The negative term indicates that the roots are imaginary.

Answer 3

The quadratic formula is x={-b++/-rt(b^2-4ac)}/2a
a=coordinate of x^2 term in this case+3
b=coordinate of x term, in this case-5
c=constant term, in this case +3
The term b^2-4ac in the formula is called the
DISCRIMINANT, because it identifies at the outset what kind of an answer to expect.
IF b^2-4ac is positive, you will have two real unequal roots. (you add and subtract to the -b term)
If b^2-4ac is 0, then you have two real equal roots.
(both roots will be the same real number)
If b^2-4ac is negative, then you are scuppered. You cannot take the square root of a negative number and get an answer in the Real number system. In this case, we say there is no solution. No real roots.

Now, for your question.
b^2-4ac has a value (-5)^2-4(3)(3),=25-36,=-11
Bad news .There are no real roots.
As my mother used to say, "Semper in Excretum"

Answer 4

discriminant = (--5)^2 -- 4*(3)*(3) = -- 11
negative discriminant gives roots are imaginary and unequal.

Answer 5

(-5)² - 4(3)(3)

25 - 36

discriminant = -9

in most cases, no solution

or, 3i if you have learned about imaginary numbers

Answer 6

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