Each wheel is a solid disk of mass 1.80000000000000 kg. On the horizontal surfaces the center of mass of each?

Question

Each wheel is a solid disk of mass 1.80000000000000 kg. On the horizontal surfaces the center of mass of each wheel moves with a linear speed of 6 m/s.
A) What is the algebraic expression for the total kinetic energy KEtotal of the rolling wheel? Express your answer in terms of the mass m of the wheel and the linear speed v of the center of mass of the wheel.

B) What is the total kinetic energy KEtotal of the rolling wheel?

Answer 1

KE = mv^2/2 + Iw^2/2 (see ref.)
I (disk) = mr^2/2
w = v/r
Iw^2/2 = (mr^2/2*v^2/r^2)/2 = mv^2/4
(ans. A:) KE = mv^2/2 + mv^2/4 = 0.75*mv^2

B. Udoit!

Answer 2

mass is moves at 3 and the out put of kineetic eng is 9