how do you solve a problem like this?
2007-09-05 16:12:34 · 6 answers · asked by smarin1987 2 in Science & Mathematics ➔ Mathematics
e^[ln(5-2x)] = e^-3
5-2x = e^-3
-2x= e^-3 - 5
x= -[(e^-3) - 5] / 2
2007-09-05 16:21:48 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Take "5" and subtract it from "3"
That will give you: -2x= -8
Then divide -2 from -2x and -8 so it will look like this: -2x/2 = -8/-2
and the solution will be: x=4
2007-09-05 23:21:06 · answer #2 · answered by i hate this 2 · 0⤊ 0⤋
ln(5 - 2x) = -3
e^[ln(5 - 2x)] = e^-3
5 - 2x = 1/e³
-2x = 1/e³ - 5
x = 5/2 - 1/(2e³)
2007-09-05 23:18:53 · answer #3 · answered by Philo 7 · 1⤊ 0⤋
x=4?
2007-09-05 23:18:47 · answer #4 · answered by Anonymous · 0⤊ 1⤋
(5-2x)=-3
-2x=-3-5
-2x=-8
x=4
2007-09-05 23:19:05 · answer #5 · answered by Anonymous · 0⤊ 1⤋
x = 5/2 - 1/(2e³)
2007-09-05 23:29:59 · answer #6 · answered by crazy_chic_luvs_rupert 2 · 0⤊ 0⤋