What is the algebraic expression for the x scalar component Fx of the force vector? Express your answer in ter

Question

A force vector has a magnitude of 544 newtons (N) and points at an angle of 39.5° below the positive x axis.
What is the algebraic expression for the x scalar component Fx of the force vector? Express your answer in terms of the magnitude F of the force vector and the angle θ that specifies the direction below the positive x axis. Remember that scalar components can be positive or negative, depending on whether they point, respectively, along the positive or negative axis.

Answer 1

Fx=544 cos (39.5) Fy = -544 sin(39.5)