Precal word problems! Please help!?

Question

I'm stuck on these 3 problems.

1.) The time t (in seconds) that it takes for a pendulum to complete one period is approximately t = 1.1 square root of L, where L is the length (in feet) of the pendulum. How long is the period of a pendulum of the length 10 ft?

2.) The time t (in seconds) that it takes for a rock to fall a distance d (in meters) is approximately t = 0.45 square root of d. How long does it take for the rock to fall a distance of 200 m?

3.) Explain why n square root of a (little n in front of the square root) and a real nth root of a need not have the same value.

PLEASE HELP! I will give best answer!

Answer 1

t = 1.1 sqrtL
t = 1.1 sqrt(10)
t = 1.1*3.16 = 3.48sec (to the nearest hundredth)

t = 0.45 sqrtD
t = 0.45 sqrt(200)
t = 0.45*14.14 = 6.36sec (to the nearest hundreth)

n*sqrt(a) = a*nrt(a)
Let use n=2 and a=4 and see if it works
2*sqrt(4) = 4*sqrt(2)
2*2 = 4*sqrt(2)
4 = 4*sqrt(2)
1 = sqrt(2)
1^2 = sqrt(2)^2
1 = 2
Doesn't work.

Answer 2

"1.) The time t (in seconds) that it takes for a pendulum to complete one period is approximately t = 1.1 square root of L, where L is the length (in feet) of the pendulum. How long is the period of a pendulum of the length 10 ft?"

That means: t = 1.1(√L)

You have L = 10, so:

t = 1.1 X (√10)

Just solve that and you'll have t!

Answer 3

So L is the length in feet of the first one, and they tell you what L is, and you can't plug in 10 for L? If they tell you what one of the variables is, then plug it in to solve for the other variable in question!!!

Answer 4

in case you have been to decrease the tire and lay it out flat you may get one circumference forward for each revolution. Divide forway velocity via circumference to get revolutions per time. via utilizing circumference you would be bearing in suggestions the diameter of the wheel.