integrate from 0 to 1/2 the equation arccos(x) dx?

Question

I can get the correct integral but when I calculate the definite integral using the limits of integration I get the wrong answer. I know you have to change the limits of integration during the problem since you use u-substitution but I still get the problem wrong. I would really appreciate any help!

I hate to tell you this, cause I am the one asking the question, but I know the answer and its .65757337 so that answer isn't right.

Sorry, i was referring to Ironduke's answer

Answer 1

integral arcos(x)dx = xarctan(x)-.5ln(1+x^2) eval'd from 0 to .5
= .5arctan.5 -.5ln(1+.25) - .5ln(1)
= .2318238045 -.1115717757 = .1202520293