help me w/ theese:
x + 2.7 > 5.5
x + 8 > 11 (the greater than sign is suppose to be a greater than/equal to sign)
2007-09-05 12:23:43 · 6 answers · asked by Reece 1 in Science & Mathematics ➔ Mathematics
treat the inequality sign exactly like you would an equals sign unless you multiply/divide by a negative number (that makes the inequality sign flip, i.e. < becomes >)
Just subtract the 2.7/8 over to the other side!
x > 2.8
x >= 3
2007-09-05 12:28:49 · answer #1 · answered by Becky M 4 · 1⤊ 0⤋
(Aside: for greater than or equal, you can use >= )
Solve an inequality just as you would solve an equality: whatever you do to one side, you must do the other side too.
But there is one extra rule...
If you multiply or divide by a negative number, you must change the direction of the inequality. For example if you have:
x > 2
then multiplying by -1 gives you:
-x < -2
Otherwise, it's pretty much the same.
2007-09-05 19:29:07 · answer #2 · answered by SV 5 · 0⤊ 0⤋
x + 2.7 > 5.5
x > 2.8
x + 8 > 11
x > 3
2007-09-05 19:27:58 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
do it the same way w/an equal sign=
x+2.7=5.5
x+2.7-2.7=5.5-2.7
x=?????
then replace the answer w/x add and c if it is true
2007-09-05 19:32:33 · answer #4 · answered by Anonymous · 0⤊ 0⤋
what's so hard? what grade are you in?
x+2.7 is at least 5.5 or greater than 5.5
thats it, it's that simple
2007-09-05 19:30:16 · answer #5 · answered by fins_etr 2 · 0⤊ 0⤋
x + 2.7 > 5.5
subtract 2.7
x > 2.8
second one
X > 3
2007-09-05 19:27:42 · answer #6 · answered by bobo 3 · 0⤊ 0⤋