how would i expand this?
2007-09-05 12:23:19 · 6 answers · asked by C.L. ~Raptors~ 4 in Science & Mathematics ➔ Mathematics
( - 3 )(2 x - 1) (2 x - 1)
( - 3 )(4 x ² - 4 x + 1)
- 12 x ² + 12 x - 3
2007-09-09 11:08:37 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Do the squared first then multiply in by the -3
So
-3(2x-1)^2=-3[(2x-1)(2x-1)]
=-3[4x^2 - 4x +1]
=-12x^2+12x-3
2007-09-05 19:29:10 · answer #2 · answered by RHShipper 1 · 1⤊ 0⤋
-3((2x-1)(2x-1)) first, FOIL terms (2x-1)
then. . .multiply everything by -3
-3*(4x^2-4x+1)
then...
-12x^2+12x-3
I think. Check against what you've learned in class.
2007-09-05 19:32:41 · answer #3 · answered by bsdetector2006 2 · 0⤊ 0⤋
(2x-1)^2 = (2x - 1)(2x - 1) = (2x)(2x)+(2x)(-1)+(-1)(2x) + (-1)(-1)
** Use the FOIL method... first, outer, inner, last terms **
= 4x^2 - 2x - 2x +1
= 4x^2 - 4x + 1 ....
But now you have to multiply each term by "-3" because your problem was... " -3(2x-1)^2 "....
so... -3(4x^2 - 4x + 1) = -12x^2 +12x -3
-3(2x-1)^2 = -12x^2 + 12x - 3
2007-09-05 19:29:40 · answer #4 · answered by blueskies 7 · 1⤊ 0⤋
-3(2x-1)(2x-1)
= -3 * 4x^2-4x+1
= -12x^2-12x+12
2007-09-05 19:28:53 · answer #5 · answered by Anonymous · 1⤊ 0⤋
-12x+3
2007-09-05 19:28:43 · answer #6 · answered by the i code 3 · 0⤊ 1⤋