( - 3 )(2 x - 1) (2 x - 1)
( - 3 )(4 x ² - 4 x + 1)
- 12 x ² + 12 x - 3
2007-09-09 11:08:37
·
answer #1
·
answered by Como 7
·
0⤊
0⤋
Do the squared first then multiply in by the -3
So
-3(2x-1)^2=-3[(2x-1)(2x-1)]
=-3[4x^2 - 4x +1]
=-12x^2+12x-3
2007-09-05 19:29:10
·
answer #2
·
answered by RHShipper 1
·
1⤊
0⤋
-3((2x-1)(2x-1)) first, FOIL terms (2x-1)
then. . .multiply everything by -3
-3*(4x^2-4x+1)
then...
-12x^2+12x-3
I think. Check against what you've learned in class.
2007-09-05 19:32:41
·
answer #3
·
answered by bsdetector2006 2
·
0⤊
0⤋
(2x-1)^2 = (2x - 1)(2x - 1) = (2x)(2x)+(2x)(-1)+(-1)(2x) + (-1)(-1)
** Use the FOIL method... first, outer, inner, last terms **
= 4x^2 - 2x - 2x +1
= 4x^2 - 4x + 1 ....
But now you have to multiply each term by "-3" because your problem was... " -3(2x-1)^2 "....
so... -3(4x^2 - 4x + 1) = -12x^2 +12x -3
-3(2x-1)^2 = -12x^2 + 12x - 3
2007-09-05 19:29:40
·
answer #4
·
answered by blueskies 7
·
1⤊
0⤋
-3(2x-1)(2x-1)
= -3 * 4x^2-4x+1
= -12x^2-12x+12
2007-09-05 19:28:53
·
answer #5
·
answered by Anonymous
·
1⤊
0⤋
-12x+3
2007-09-05 19:28:43
·
answer #6
·
answered by the i code 3
·
0⤊
1⤋