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-1> 2r-5> -9

2007-09-05 12:12:04 · 7 answers · asked by whereistheemu 1 in Science & Mathematics Mathematics

7 answers

4 > 2r > -4
2 > r > -2

2007-09-05 12:14:51 · answer #1 · answered by cjcourt 4 · 0 0

No.

-1 > 2r - 5 > -9

-1 + 5 > 2r - 5 + 5 > -9 + 5

4 > 2r > -4

2 > r > -2
-2 < r < 2
or r (member of range) (-2,2)

2007-09-05 19:21:32 · answer #2 · answered by mathmannix 3 · 0 0

-1 > 2r-5 > -9

Add 5 to all three figures :
4 > 2r > -4

Divide by 2 :
2 > r > -2
That's your solution

2007-09-05 19:25:41 · answer #3 · answered by skeptik 7 · 0 0

2r - 5 . . . . is between -1 and - 9
4 > 2r > 4
2 > r > 2 . . . it is a point
yes no solution

2007-09-05 19:18:57 · answer #4 · answered by CPUcate 6 · 0 1

4>2r> - 4

divide all by 2

2>r>-2

s.s= ] 2,-2 [

2007-09-05 19:15:31 · answer #5 · answered by Anonymous · 0 0

There is a solution. Split the problem in two
2r-5 < -1
2r-5 > -9

2r < 4 --> r < 2
2r > -4 -->r > -2

-2 < r < 2

2007-09-05 19:19:22 · answer #6 · answered by J S 2 · 0 1

sure

2007-09-05 19:14:02 · answer #7 · answered by Tinsley 3 · 0 2

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