i need to know an easy way to factor these. i know one way of doing it but 19 is prime and i cant do that here! pls help me.
i am also confused with 5f^2+48f+27 and 8d^2+d-30
2007-09-05 12:05:03 · 4 answers · asked by Izzie 2 in Science & Mathematics ➔ Mathematics
id also like to know how u did it? pls?
2007-09-05 12:21:07 · update #1
[Sorry to say, the answer given by 'RAVEN' is WRONG]
1)
6x^2+19x+15
= 6x^2 + 10x + 9x + 15
= 2x (3x + 5) + 3 (3x + 5)
= (3x + 5) (2x + 3) [Answer]
2)
5f^2+48f+27
= 5f^2 + 45f + 3f + 27
= 5f (f + 9) + 3 (f + 9)
= (5f + 3) (f + 9) [Answer]
3)
8d^2+d-30
= 8d^2 + 16d - 15d -30
= 8d (d + 2) - 15 (d + 2)
= (8d - 15) (d + 2) [Answer]
2007-09-09 17:28:57 · answer #1 · answered by defeNder 3 · 0⤊ 0⤋
Question 1
( 3 x ² + 5 ) ( 2 x ² + 3 )
Question 2
( 5 f + 3 ) ( f + 9 )
Question 3
( 8 d - 15 ) ( d + 2 )
2007-09-09 19:59:36 · answer #2 · answered by Como 7 · 0⤊ 0⤋
i assume which you meant to place in writing 6x^2 + 19x - 15 =0 employing the quadratic formulation with a = 6, b = 19 and c=-15 [-19 plus or minus sqrt(19*19 +4*6*15)]/12 [-19 plus or minus sqrt(721)]/12
2016-12-31 13:54:51 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(3x+5)(2x+3)
(5f+9)(f+3)
(8d+15)(d-2)
2007-09-05 12:12:39 · answer #4 · answered by Heyhey 5 · 1⤊ 0⤋