What voltage is required to store 7.2 x 10^-5 C of charge on the plates of a 7.0 µF capacitor?
2007-09-05 11:38:47 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
V = Votage, Q = Charge and C = Capacitance
V = Q / C
V = 0.000072 coulomb / 0.000007 microfarad
V = 10.29
2007-09-05 11:49:34 · answer #1 · answered by arinc_429 2 · 0⤊ 0⤋
use the equation that relates to charge, voltage, and capacity.
that is, q = C x V and V = q divided by C
Check the book, Intro Physics (Algebra Based) it has the same example as you, but with a 6.0 uF capacitor.
2007-09-05 11:59:04 · answer #2 · answered by LG 3 · 0⤊ 0⤋
05.CV^2 = energy
Guess charge is V*C coulombs
so 7.2e-5/7e-6 = 10.286 Volts
2007-09-05 11:52:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋
q=cV; V=q/c
Find V by plugging in the numbers
2007-09-05 11:52:47 · answer #4 · answered by Snowflake 7 · 0⤊ 0⤋