Algebra 1 project help?

Question

Okay, I'm taking Algebra 1 this year, and we have this project where we get a year (my year is 1900) and make a math problem out of it.

The math problem that I made is:

[(867*2)-(7*204)]*(1896/316)+[... (The whole thing doesn't show up, but only the first part is important).

Well, I know that the problem equals 1900 (I made up the problem and checked it), but I don't understand if I'm supposed to use brackets in the problem, or if it's correct just to put an extra set of parentheses like: ((867*2)-(7*204)).

This is for a major grade project, so I need to know which is the correct way of writing the problem please!

Answer 1

Hmm, good question. I have actually seen it written both ways - with brackets or an extra set of parantheses. I personally use the brackets so that I don't forget to put the bracket at the end of the set of numbers. With double parantheses, you may tend to forget to include a final parantheses.

Good luck!

Answer 2

a million. it fairly is like fixing a popular equation yet you need to do the comparable factor to each part of the inequality. a) upload 2 to all factors to get 8 < x < 12 2. Absolute fee is once you mostly take the quantity and make it valuable if its damaging. b) (if the a million represents genuinely the linked fee sign) remedy it like a popular equation. x=14. if the respond become -14 then genuinely the linked fee of it may well be 14. a million. seem for numbers that when placed into 2 binomials and foiled, might equivalent the trinomial. a) (x+3) (x-5) b) (x+10) (x+3) 2. 4x^2 + 32x + 60 factor out 4 first to get (4) (x^2 + 8x + 15) then placed into binomials (4) (x+3) (x+5) 3. take each and each binomial seperately and remedy for x a) take (x-3)=0 first and get x=3, then take (x-7)=0 to get x=7. your recommendations are x=3,7. interior the 2nd, first factor it into to binomials (x+5) (x-5)=0 and remedy for each seperately getting x=5, -5 a million. x= -b +/- the sq. root of b^2 - 4ac throughout 2a a) a=3, b=2, c=-6 plug them into the quadratic equation somewhat than a, b, and c to get your 2 recommendations while a trinomial isn't factorable

Answer 3

Suggestion only
try converting 1900 . . to . . . 2007
use * / + - and manipulate all the digits 19002007
or make a puzzle contest to your student. . . give a prize
you will ease your burden . . . let the student have activity

or . . . . . . . assign a word to each number ,, ramble it

selection A . . . . . . selection B
G - 9 . . . . . . . . . . . . . . . K - 1
O - 0 . . . . . . . . . . . . . . . G - 9
D - 0 . . . . . . . . . . . . . . . N - 0
K - 1 . . . . . . . . . . . . . . . O - 0
N - 0 . . . . . . . . . . . . . . . S - 2
O - 0 . . . . . . . . . . . . . . . O - 0
W - 7 . . . . . . . . . . . . . . .O - 0
S - 2 . . . . . . . . . . . . . . . W - 7

announce that numbers are assigned to a each of the letters.
you let them guess the word

Answer 4

extra brackets is better because clearer.

so this

[(867*2)-(7*204)]*(1896/316) + ...

or (is the same)

[867*2 - 7*204]*(1896/316) + ....

Answer 5

i am pretty sure either way is correct but brackets are much easier to understand so i would use the brackets.