math help??? slope stuff? kinda??

Question

What are the 2 points that these equations go through?
(or something like that, my teacher said not to graph them just dinf the 2 points)

1. y = -3/5x - 12/5

2. 2/3x + y/3 = -1/3

3. 3/5y - x/5 = -6/5

4. 4/5 = - 1/3x - 3/4y

Answer 1

Set y=0 and solve for. Set x = 0 and solve for y
1. y = -3/5x - 12/5
0 = -3/5 x -12/5 so x= -4 and one point is (-4,0)
y = 0 -12/5 so (0, -12/5 is another point

2. 2/3x + y/3 = -1/3
2/3 x = 0 = -1/3 so x -1/2 and (-1/2,0) is one p[oint
0 + y/3 = -1/3 so y = -3 and (0,-3) is another point

3. 3/5y - x/5 = -6/5
0 -x/5 = -6/5 so x =6 and (6,0) is one point
3/5 y = -6/5 so y = -2 so (0,-2) is another point

4. 4/5 = - 1/3x - 3/4y
4/5 = -3/4 y so y= -16/15 so (0, -16/15) is one point
4/5 = -1/3x so x = -12/5 and (-12/5,0) is another point

Answer 2

first u have to change all the equations so that they say "y=" as the first part, like the first one. then just plug in a number for X and solve for Y and those are the points. so for #1 plug in 0 for X which makes Y= -12/5. So a point that the first equation goes thru is (0,-12/5).