What is the domaian of f(x)=x^2, f(x)=1/x, and f(x)=square root of x+2? If possible, explain your answer.?

Question

What is the domaian of f(x)=x^2, f(x)=1/x, and f(x)=square root of x+2? If possible, explain your answer.

Answer 1

The domain ofa function f(x) is the set of real numbers x such that f(x) gives a real numbered-value.

so for x^2, the domain is all the real numbers, for 1/x, the domain is all the real numbers except for 0 (as 1/0 is undefined) and for √x +2 the domain is all the real numbers from 0 upwards (negative values of x give complex values.
If you meant √(x+2), then its all the real numbers from -2 upwards.

Answer 2

The domain of f(x)=x^2 is the set of all numbers in the Real number system. Reason: There is no number that cannot be squared.

f(x)=1/x, all numbers except 0. Division by zero is not permitted.
f(x)=rt(x+2), the set of all numbers where x is equal to or greater than -2. Reason: Lower than x=-2 and you would be taking the square root of a negative number- which cannot be done in the real number system.

Answer 3

I'll give the explanation, not the answer.

The domain is the set of all values that can be used as input.
for example, in the second function
f(x) = 1/x,
x can be any value EXCEPT 0. 0 cannot be in the domain.
An exact definition of the domain usually requires the identity of the field in whch you are working. For example, if you are working ONLY with integers, then the domain of f(x) = 1/x can only be {-1, +1} because 1/x for anything else is not an integer (so, it does not exist in that field).

If you are working with real numbers, you can square anything, you can inverse anything except 0 and you cannot take the square root of negative values.

Answer 4

1.414