ok so i grabbed the wrong binder with my notes on how to do these equations, so i cant remember how to do them and its realy confusing how to add negatives positives and multiplying them! so can some one help explain how to do them!?
here are some equations i dont get...
For both equations x=3, y=2 and z=1
1) x² - y² + z²=
2) 3xy-yz+2
2007-09-05 10:16:04 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1.
(3)^2 - (2)^2 + (1)^2
9-4+1=6
2.
3(3)(2)-(2)(1)+2
18-2+2=18
2007-09-05 10:23:04 · answer #1 · answered by Justin 3 · 0⤊ 0⤋
1) x^-y^+z^
3^-2^+1^
9-4+1
5+1
6
2) 3xy-yz+2
3x3x2-2x1+2
18-2+2
16+2
18
2007-09-05 10:28:29 · answer #2 · answered by nebby 3 · 1⤊ 0⤋
1) 3^2 - 2^2 + 1^2
9 - 4 + 1
6
2) 3x3x2 - 2x1 + 2
18 - 2 + 2
16 + 2
18
2007-09-05 10:30:26 · answer #3 · answered by hesterific 2 · 0⤊ 0⤋
(second problem) You would first insert the numbers in the variables' place like this:
3(3)(2)-(2)(1)+2
Remember the order of operations:
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
So you would first multiply 3(3)(2), and get 18.
Then you would multiply (2)(1) and get 2.
Then you would add 18 and 2 and get 20.
Then subtract 2 from 20 and get 18.
2007-09-05 10:28:23 · answer #4 · answered by Cham Cham 2 · 0⤊ 0⤋
#1. = 12
#2.= 2
2007-09-05 10:21:12 · answer #5 · answered by Anonymous · 0⤊ 2⤋
- x - = +
- x + = -
+ x + = +
2007-09-05 10:26:28 · answer #6 · answered by gjmb1960 7 · 0⤊ 1⤋