plz help
2007-09-05 09:32:54 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If f(x) = -f(x) for any value of x then the function is even.
Visually, an even function will be symmetric relative to the y-axis.
2007-09-05 09:38:49 · answer #1 · answered by Mathsorcerer 7 · 0⤊ 0⤋
A function f(x) is even if and only if f(x)=f(-x), and odd if and only if f(-x)=-f(x).
So, let f(x)=1-cosx, then f(-x)= 1-cos(-x)=1-cosx (since cosx is even), hence f(x)=f(-x) and 1-cosx is even.
A better way of thinking about odd and even functions is that an even function is symmetrical about the y axis, (think of the cos curve) and an even function is 'antisymmetrical' (think of the sin curve.
2007-09-05 09:46:59 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Y=1-cos x
=1-cos(-x)
=1-cosx even
2007-09-05 09:40:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Cos X Even Or Odd
2017-02-24 07:15:17 · answer #4 · answered by ? 4 · 0⤊ 0⤋
f(-x) = 1-cos(-x) = 1-cos(x) = f(x)
Therefore the function is even
2007-09-05 09:41:10 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
it is an even function.
an even function has the property : f(-x) = f(x)
an odd function has the property : f(-x) = -f(x)
since cos(-x) = cos(x) you get that Y(-x) = Y(x)
2007-09-05 09:41:18 · answer #6 · answered by Christophe G 4 · 0⤊ 0⤋
Y(x)=1-cosx
Y(-x)= 1-cos(-x)
=1- cosx=Y(x)
so Y(x) is even function of x. ANS
2007-09-05 09:41:18 · answer #7 · answered by Anonymous · 0⤊ 0⤋