what are the x intercepts of the porabola Y=2x^2 + 5x +3?

Answer 1

Find x's for 0=2x^2+5x+3.
Factoring it, (2x+3)(x+1)=0.
So, 2x+3=0, so 2x=-3,
so, x=-3/2.

So, x+1=0,so x=-1.
SO, x=-3/2 and x=-1.

Answer 2

Hi,
In these book problems it's always best to check and see if the quadratic equation can be factored into two binomials (Binomials have two terms.) with whole number coefficients. So, let's take a look at it.

1) Write the factors of 2x² as the first terms of two multiplied binomials since everything is positive, we can also add the plus signs in each binomial.
(2x + ?a )(x +?b )= 0

2) Now, the factors of 3 are 3 and 1 and they go where ?a and ?b (unknown a and unknown b) are located. So, to decide which goes where, we want the sum of the products of the inside (?a *1) and the outside terms (2*?b) to equal 5, the middle term of the original equation. If we write this out -- which may not be helpful -- we have this:
2*(?b) +(?a) *1= 5

3) So, if we put and 3 for ?a and 1 for ?b we have this:
2*1 + 1*3 = 5
And substituting we have this:
(2x +3)(x +1) = 0
Now, using the zero factor theorem, set each factor equal to zero and solve for x.
2x + 3 = 0
2x = -3
x = -3/2
x+1 = O
x = -1
So, the x-intercepts are {-3/2, -1}

Hope this helps.
FE

Answer 3

The x-intercepts are the points where the parabola crosses
the x-axis; that is, where y = 0. Therefore if we let y = 0 we
can say: 2x**2 + 5x + 3 = 0 and use the quadratic formula.
Then x = (-5 ±√((5*5)-(4*2*3)))/2*2 = (-5 ± √(25 - 24))/4
or: x = (-5 ± 1)/4 Then x can equal (-5 + 1)/4 or -1
or x can equal (-5 - 1)/4 or -1½
Therefore the x-intercepts are -1 and -1½.
Hope this helps.

Answer 4

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