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hello everybody i got this problem at school that i am like half way into figuring out but i am stuck and i would realy appreciate your help
here is the problem:

A British Concorde(BC) and a French Concorde(FC) flew in opposite direction around the world, a distance of 40 000km. The BC covered half of its flight distance at a speed of 2500 km/h and the other half at a speed of 1000 km/f. The FC spent half of its flight time at 2500 km/h and the other half at 1000 km/h. Which concorde completed the trip first, and by how many hours did it beat the other?

thanks alot for any help

2007-09-05 08:36:02 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

The statement of the problem implies that the rotation of the earth should be ignored since no mention is made as to which plane is flying in which direction.
BC:
t = t1 + t2
t = D1/r1 + D2/r2
t = 20000/2500 + 20000/1000
t = 28.0 hr.

FC:
t1 = t2
D1/r1 = D2/r2
D1/2500 = (40000 - D1)/1000
1000D1 = 100000000 - 2500D1
3500D1 = 100000000
D1 = 28571.4
t1 = 28571.4/2500
t1 = 11.4286hr
t1 + t2 = 2t1 = 22.8572hr
28.0 -22.8572 = 5.1428 hr.
FC wins by 5.1428 hours.

2007-09-05 09:33:24 · answer #1 · answered by jsardi56 7 · 0 0

just remember about the spin of the earth, past that i think youll get it by yourself.

2007-09-05 08:48:32 · answer #2 · answered by Koozie the chemist 4 · 0 0

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