How do you solve:
angle AOC = 7x-2, angle AOB= 2x+8, angle BOC= 3x+14
And it says to solve for x, but how am I supposed to do that with three of them and nothing to set them equal to? Thanks.
2007-09-05 08:19:47 · 7 answers · asked by ? 4 in Science & Mathematics ➔ Mathematics
First assume there is a plane that contains all four points. Then, from the problem definition, the sum of the three angles has to total 360. So, (7x -2) + (2x + 8) + (3x + 14) = 360. And you can solve that, of course... :)
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OK, other posters have a valid point: if O is inside triangle ABC, the above formula gives the answer. However, if O is outside triangle ABC, you get a different answer. In fact, I think you may get three different answers, since having any two angles equal the third angle all look like valid solutions.
2007-09-05 08:28:22 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You can write that AOC = AOB + BOC (this is true wherever B, if B is "lower" than A and C then BOC have a negative value).
you get 7x-2 = 2x+8 +3x+14 or x = 12
2007-09-05 08:31:46 · answer #2 · answered by Christophe G 4 · 1⤊ 0⤋
angle AOC=angle AOB+angleBOC
7x-2=2x+8+3x+14
7x-5x=22+2
2x=24
x=12. ANS.
2007-09-05 08:28:33 · answer #3 · answered by Anonymous · 1⤊ 0⤋
It is not clear what the figure having these angles looks like
The points might be arranged like
A . . . B . . . C
.
.
. . . . O
In which case angle AOC = angle AOB + angle BOC
or
7x - 2 = (2x + 8) + (3x + 14)
7x - 2 = 2x + 8 + 3x + 14
7x - 2 = 5x + 22
2x = 24
x = 12
2007-09-05 08:32:57 · answer #4 · answered by Anonymous · 1⤊ 0⤋
ABC must be a triangle and O is a point inside the triangle. The three angles therefore add up to 360 degrees. So
7x-2 +2x+8 +3x+14 = 360
12x = 340
x = 28 1/3
2007-09-05 08:37:17 · answer #5 · answered by ironduke8159 7 · 0⤊ 1⤋
What does the picture look like? Is OB a line between lines OA and OC?
If so, then...
AOB + BOC = AOC
so...
(2x + 8) + (3x + 14) = (7x - 2)
solve that equation for x.
2007-09-05 08:30:06 · answer #6 · answered by Mathematica 7 · 0⤊ 0⤋
first-what kind of a polygon is it? if it is a triangle = 180, if it is a quadrilateral= 360
i think O is the center, so all the angles are part of a center. therefore you make them equal to 360 because a center is always 360 degrees.
2007-09-05 08:29:11 · answer #7 · answered by Anonymous · 0⤊ 0⤋