EXTREME HELP NEEDED! 7th grade math!?

Question

10 distinct points are identified on the circumference of a circle. How many different convex quadrilaterals can be formed if each vertex must be one of these points?

Best answer will be chosen on explanation+clarity.

I need the explanation by thursday(tomorrow)! please?

=) thanks.

Answer 1

A polygon is said to be convex if it fully contains all line segments
drawn between any two points of the polygon.
Once four vertices have been selected, the quadrilateral is
determined, regardless of the order of the vertices. So this is just a
combination problem. We seek the number of combinations of 10
things taken 4 at a time:
C(10, 4) = 10C4 =
10!
4! (10 − 4)!
=
10 × 9 × 8 × 7
4 × 3 × 2 × 1
= 10×3×7 = 210
I think that's it.
I hope that's it.
I'm in 10th grade.
I googled. the question.
So I don't know if it's right.

Answer 2

triangle
quadrilateral
pentagon
hexagon
heptagon
nonagon
decagon

I count seven

Edit:

Sophomore has a good point. You could take any of these figures and choose different vertices, giving you many more possibilities. OTOH, I think that's a bit advanced for 7th grade and I'll stick with my answer.

Answer 3

You do the math.