whats is the domain of the function 1/(6x+1)^(1/2)?

Question

can i write the domain as -1/6Uinfinity

Answer 1

(6x+1)^(1/2) equals the square root of (6x+1).

Set 6x + 1 = 0. x will equal -1/6. The square root of (6x + 1) has to be greater than or equal to 0 (you cannot take the square root of a negative number), so the domain, or possible values of x, are

x such that x is greater than or equal to -1/6

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The post below mine is correct. GREATER than -1/6, not greater than OR EQUAL to.

Answer 2

If x = -1/6, the expression 6x + 1 becomes zero. Because this value of x would force a divide by zero when evaluating the function, it is not in the domain.

Likewise, if x < -1/6, the argument under the square root becomes negative and will not give a result that is a real number. If you are restricted to real numbers for function arguments and values, that means x < -1/6 isn't in the domain either.

For values of x > -1/6, no such problems occur in the evaluation of the function, so x > -1/6 is the domain of the function.

Answer 3

The variable X must be greater than a negative 1/6th. If it is exactly -1/6, then the denominator is zero and X becomes infinite. If it is less than -1/6, the denominator is the square root of a negative number. Such numbers actually are used in math, but they are called "imaginary numbers".

Answer 4

there are 2 issues that would restrict the area of this function: a million) while the numerator is 0 (why? because of the fact then you definately could have a million/0 which isn't defined). this happens while the expression under the unconventional is 0, in different words while 14x+11=0, or while x=-11/14. so as that fee of x is excluded from the area 2) while the expression under the unconventional is decrease than 0, i.e. while this is destructive (why? because of the fact, assuming we are limited to reals, sq. root of destructive numbers is undefined). this happens while 14x+11 < 0, or while x < -11/14. combining the two situations, we could desire to exclude all x <= -11/14. hence the area is: x > -11/14 as they are saying, trouble-free simon met that pieman (i.e., you have been schooled)

Answer 5

its actually pretty simple. you just have to simplify it to an algorythym of basic algebra. first find out the brackets. and divide it into .16x+1)and then to the power of .5 and then isolate the x by dividing the .5 with .16 and minus 1. now its .5/.16 minus 1=x. the answer is 2.125

Answer 6

this function exists for x not = -1/6

Answer 7

shouldnt you be doing your own homework?