Could you help me solve these equations so that I can graph them?

Question

#1. 2x=y+1, 2x-y=5

#2. 3x+2y=8, 6x+4y=16

Thanks so much for the help!

Answer 1

1.
2x = y + 1
y = 2x - 1
The slope is 2 and the 'y' intercept is '-1'.

2x - y = 5
y = 2x - 5
The slope is '2', parallel to above line, and 'y' intercept is '-5'.

2.
3x + 2y = 8
2y = -3x + 8
y = -3/2x + 4
The slope is '-3/2' and the 'y' intercept is '4'.

6x + 4y = 16
4y = -6x + 16
y = -6/4x + 4
y = -3/2x + 4
These two lines in Q2 are co-linear, that is they will appear as one line on the graph.

Answer 2

1) 2x=y+1 ,2)3x+2y=5
2x-1=y ,(3/2)x-(5/2)=y

2x-y=5 ,6x+4y=16
2x-5=y ,(3/8)x-4=y

Answer 3

Put the equations in slope-intercept form: y = mx + b,
where m = your slope and b = your y intercept.

1.
2x = y +1
>>> y = 2x - 1

2x -y = 5
>>> y = 2x - 5


2.
3x + 2y = 8
2y = -3x + 8
>>> y = -1.5x + 4

6x + 4y = 16
4y = -6x + 16
>>> y = -1.5x + 4

Answer 4

If you are looking for common solutions, for number one there is no common solution because the lines are parallel.

Number 2 it is the same equation so graphing them gives you the same line.

Answer 5

Are you kidding? Both the equations are stupid.
( 1 )The same expression having two values and
( 2 )The same expression repeated. Stop wasting our time. After all, we intend to help you sincerely.