1/3x + 3
2007-09-05 03:21:38 · 5 answers · asked by Michael S 1 in Science & Mathematics ➔ Mathematics
i donot know
2007-09-09 01:21:38 · answer #1 · answered by bansal 4 · 0⤊ 0⤋
I found the way that you have presented the question confusing. Do you mean find the value of the function when x = 0, in which case you get:
1/0 + 3 = 3, which is undefined because of the 1/0, or did you mean find the value of x which makes the function zero, in which case:
1/3x + 3 = 0, so
1/3x = -3, so
1 = -9x, so
-1/9 = x.
Check: 1/(3*-1/9)
=1/-1/3
= -3, so it`s correct.
Hope this helps, Twiggy.
2007-09-05 04:03:17 · answer #2 · answered by Twiggy 7 · 0⤊ 0⤋
1/3x + 3 = 0
Multiply both sides of the equation by 3
3(1/3x) + 3(3) = 3(0)
x + 9 = 0
Transpose 9
x + 9 - 9 = 0 - 9
x = - 9
- - - - - -
Check
1/3x + 3 = 0
1/3(- 9) + 3 = 0
- 9/3 + 3 = 0
- 3 + 3 = 0
0 = 0
- - - - - - -s-
2007-09-05 03:44:28 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
F(0) = 0/3 + 3 = 3
2007-09-05 03:26:15 · answer #4 · answered by gebobs 6 · 0⤊ 1⤋
1/3x+3=0
1/3x=-3
x=-9
2007-09-05 03:27:30 · answer #5 · answered by Grampedo 7 · 0⤊ 0⤋