WTF??? I've never seen anything like this!!! Can anyone help me out?
2007-09-05 02:13:25 · 5 answers · asked by nunyan 2 in Science & Mathematics ➔ Mathematics
This seems to be the formula for the area of a trapezium.
A = (h/2)*(b+c)
You need to get 'b' by itself so get rid of the h/2 out the front by multiplying both sides by 2/h.
You get: 2A/h = b + c
To get b by itself get rid of the c on the right hand side by subtracting it from both sides so you end up with:
b = (2A/h) - c
2007-09-05 02:21:44 · answer #1 · answered by Manny L 3 · 0⤊ 0⤋
A=1/2(h)(b+c)
1/2*h*(b+c)=A
h(b+c)=2A
b+c=2A/h
b=(2A/h)-c
2007-09-05 09:20:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2 A = h (b + c)
2 A = h b + h c
h b = 2 A - h c
b = ( 2 A / h ) - c
2007-09-05 10:39:35 · answer #3 · answered by Como 7 · 1⤊ 0⤋
1. multiply both sides by 2 --> 2A = h (b+c)
2. divide by h --> 2A/h = b+c
3. subtract c --> 2A/h - c = b
2007-09-05 09:18:00 · answer #4 · answered by John V 6 · 1⤊ 0⤋
A = 1/2 (h) (b+c)
(b+c) = 2A/h
thus... b = 2A/h - c
2007-09-05 09:18:27 · answer #5 · answered by Jocel B. Bartolay 2 · 1⤊ 0⤋