2007-09-04 21:54:34 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
A = area of base
h = height
V = volume of pyramid.
V = (1/3) A h units ³
2007-09-10 19:29:30 · answer #1 · answered by Como 7 · 2⤊ 0⤋
A pyramid has a base and triangular sides which rise to meet at the same point. The base may be any polygon such as a square, rectangle, triangle, etc. The general formula for the volume of a pyramid is:
Area of the base * Height * 1/3
The volume of a pyramid with a rectangular base is equal to:
Length_of_base * Width_of_base * Height * 1/3
=)
2007-09-05 05:34:31 · answer #2 · answered by ♪£yricảl♪ 4 · 0⤊ 0⤋
First you must find the area of the base, be it a triangle, square, circle, anything, just find the area of the base, denoted as B.
the volume of the pyramid is then V = 1/3 * B * h were h is the height of the pyramid.
2007-09-09 19:20:33 · answer #3 · answered by Merlyn 7 · 0⤊ 1⤋
The volume of a pyramid is 1/3Bh where B is the area of the base (formula will depend on the shape) and h is the height of the pyramid
2007-09-05 05:00:21 · answer #4 · answered by Tom :: Athier than Thou 6 · 1⤊ 0⤋
That's easy
V=1/3x(AH)
A= Base area
H=Height
This can be proven using calculus:
It can be proved using similarity that the dimensions of a cross section parallel to the base increase linearly from the apex to the base. Then, the cross section at any height y is the base scaled by a factor of (h-y)/h , where h is the height from the base to the apex. Since the area of any shape is multiplied by the square of the shape's scaling factor, the area of a cross section at height y is (A/h^2)*(h-y)^2 .
The volume is given by the integral (this is easier to explain using ms equation but here goes):
\fract{A} {h^2}\int_0^h( h-y)^2\, dy=fract{-A} (3h^2} (h-y)^3\biggI_0^h=\fract{1} {3}Ah
2007-09-05 05:18:40 · answer #5 · answered by dewo96 2 · 1⤊ 0⤋
Volume of a pyramid, calculus, not algebra.
http://www.vias.org/calculus/06_applications_of_the_integral_01_05.html
2007-09-05 05:11:44 · answer #6 · answered by stolsai 5 · 0⤊ 1⤋
volume of a pyramid is not solved in calculus but in solid mensuration...duh!!
V= area of the base multiplied by the height of the pyramid..
2007-09-11 20:03:18 · answer #7 · answered by aldrin 2 · 0⤊ 2⤋
V = a(base) * h * 1/3, where:
a(base) = area of base, and
h = height of pyramid
2007-09-05 04:59:50 · answer #8 · answered by Anthony P - Greece 2 · 2⤊ 0⤋
Center of mass of pyramid is at 3/4 th of its height from its vertex on its on axis.
2007-09-11 05:21:26 · answer #9 · answered by SWETHA R 1 · 0⤊ 2⤋
Let L and W = length and width of base, respectively; H = height
Volume:
= ([L * W] * H) / 3
= (LW * H) / 3
= LWH / 3
= 1/3LWH
2007-09-09 03:53:03 · answer #10 · answered by Jun Agruda 7 · 3⤊ 0⤋