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If the interger being subtracted is GREATER than the other interger, is the answer is negative or positive?







If the interger being subtracted is LESS than the other interger, is the answer is negative or positive?













I know it's Grade 5 Math.

2007-09-04 21:06:57 · 7 answers · asked by SCOOOOOOByyyyyyyyyyyyyyy-dddooo! 2 in Science & Mathematics Mathematics

7 answers

2. postive



1. negative















See Hougton Mifflin Math Grade 5 teacher edition.

2007-09-05 21:49:20 · answer #1 · answered by The one 4 · 0 0

If the integer being subtracted is GREATER than the other integer, then you are taking away more than you started with. So the answer is negative.

If the integer being subtracted is LESS than the other integer, then you are taking away less than you started with, so you'll still have something left. So the answer is positive.

If your integers are not positive, then the above intuitive reasoning breaks down a bit, but the answers are still the same.

2007-09-04 21:12:33 · answer #2 · answered by Anonymous · 0 0

lets assume the subtraction is of the form
x-y
where x & y are integers
if x>y then the answer will be postive
if x

in terms of your question, the answer to first part of your question is NEGATIVE
and the answer to the second part of the question is POSITIVE

2007-09-04 21:13:15 · answer #3 · answered by shubham_nath 3 · 0 0

lets assume the subtraction is of the form
x-y
where x & y are integers
if x>y then the answer will be positive
if x

in terms of your question, the answer to first part of your question is NEGATIVE
and the answer to the second part of the question is POSITIVE
it will be the opposite of 1st case

2007-09-04 21:15:50 · answer #4 · answered by Anonymous · 0 1

I'm guessing that you're probably starting out with both integers being positive, so yes. You're right on both counts.

Doug

2007-09-04 21:13:18 · answer #5 · answered by doug_donaghue 7 · 0 0

Negative

Positive

2007-09-04 21:11:40 · answer #6 · answered by picaresque_82 2 · 0 0

a million) you opt for this formula y-y1-m(x-x1) perceive the variables x1=a million, y1=3, m=2 plug it in y-3=2(x-a million) simplify y-3=2x-2 upload 3 to the two facets y=2x+a million lower back y-y1=m(x-x1) perceive the varables x1= -6, y1=5, m= a million/3 plug it in y-5=a million/3(x+6) simplify y-5=a million/3x+2 y=a million/3x+8

2016-10-04 00:31:52 · answer #7 · answered by richberg 4 · 0 0

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