f(x) = ( 5x^3-10x^2 ) / ( x - 2 ) x not equal to 2
k x equal to 2
2007-09-04 20:09:43 · 4 answers · asked by i<3WL 2 in Science & Mathematics ➔ Mathematics
where's kx in the equation?
2007-09-04 20:15:43 · answer #1 · answered by forgetfulpcspice 3 · 0⤊ 0⤋
According to the definition of continuity, at x=2
lim (x->2) f(x) = f(2)
lim(x->2)f(x) = lim(x->2)(5x^3 - 10x^2)/(x - 2) =
= lim(x->2) 5x^2 * (x - 2) / (x - 2) = lim(x->2) 5x^2 =
= 5*2^2 = 5*4 = 20
Pssst Doug!!!!!1 Give me a thumb down, but remember that my answer can be chosen as the best just the same.
2007-09-04 20:16:52 · answer #2 · answered by Amit Y 5 · 1⤊ 0⤋
The only thing that will work is to make k = 0 so that the x term in the denominator goes away.
Doug
Edit:
Psssttt!!!! Amit Y. Existence of a limit at a point does -not- imply continuity at that point. In fact, at x=2, f(x) = 0/0.
Doug
2007-09-04 20:17:45 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
component the numerator to get 8x^2(x-2)/(x-2). Cancel the x-2, leaving 8x^2. whilst x = 2, it is 32, so as that could desire to be your fee for ok word that f(x) = 8x^2 for all factors different than whilst x=2, the place this is undefined. including in f(2)=32 patches the hollow.
2016-11-14 05:50:20 · answer #4 · answered by ? 4 · 0⤊ 0⤋