Help please!
Two charges are located along the x axis: q1 = +6.0 µC at x1= +4.0 cm, and q2 = +6.0 µC at x2 = -4.0 cm. Two other charges are located on the y axis: q3 = +3.0 µC at y3 = +5.0 cm, and q4 = -8.0 µC at y4 = 7.0 cm. Find the net electric field magnitude and direction) at the origin.
2007-09-04 20:09:01 · 3 answers · asked by GSU 1 in Science & Mathematics ➔ Physics
calculating the resultant horizontal electric field:
E = Q/ [4(pi)(epsilon)(r)^2]
since the 2 electric charge have the same mag. and are acting in the direction, the vector sum of the 2 fields is 0.
calculating the resultant vertical electric field:
E= 3.0 µ/ [4(pi)(epsilon)(5)^2] + -8.0 µ/ [4(pi)(epsilon)(7)^2]
direction of field is pointing downwards
2007-09-04 21:13:02 · answer #1 · answered by superlaminal 2 · 0⤊ 3⤋
How could desire to i'm getting ? if the two actually considered one of my expenditures are 4 micro C placed at x= 1m and x =-1m and that i could want to calc the fee E of the internet electric powered field at y= 0.6m? idk what to anticipate x and y to plug into arctan?, the only way i think of like i'll do it finally finally end up being 0 by using utilising certainty it may desire to nicely be arctan(0/0.6)
2016-10-18 00:20:16 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Just calculate the e-field vector caused by each of the charges by itself (as if none of the other charges were present), and then add them all up.
It really is that simple ☺
Doug
2007-09-04 21:10:37 · answer #3 · answered by doug_donaghue 7 · 0⤊ 5⤋