Hi, I've been having troubles with problems like these. I understand the concepts but can't get the problem right. Please explain and write problem. Please and early thank yous:
3a(a(squared)-2a+1)
The a squared is an a with the little 2 exponent over it
Ty again
2007-09-04 17:16:59 · 5 answers · asked by nobody 3 in Science & Mathematics ➔ Mathematics
thats what i got but its wrong...
i think...
2007-09-04 17:24:25 · update #1
3a(a(squared)-2a+1)
if you are trying to solve for a then it is really simple
factor the equation in the parenthesis
so it would be 3a((a-1)(squared))
then a could only equal 0 and 1
2007-09-04 17:31:52 · answer #1 · answered by SK07KS 2 · 0⤊ 0⤋
As Laura noted, it isn't clear exactly what you want to do with this. Note that the term in the ( ) is a perfect square, so you can factor to
3a * (a-1)^2
2007-09-04 17:32:55 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
ok, well first you're going to have to multiply everything inside the parentheses by 3a. your result would be: 3a^3-6a^2+3a. I think that your problem is your exponent laws. If you know those, you should be fine.
2007-09-04 17:26:17 · answer #3 · answered by Linnea 2 · 0⤊ 0⤋
hey, when you type, you write "a squared" as a^2
just so you know for next time
so I think this is the question
3a(a^2 - 2a + 1)
do you just need to expand and simplify? That is what I assume.. so here goes
3a^3 - 6a^2 + 3a
Thats it... msg me if you need more help
2007-09-04 17:22:32 · answer #4 · answered by Albus 2 · 0⤊ 0⤋
Sorry but you should give first the number substituted by A...
2007-09-04 17:23:54 · answer #5 · answered by Jasper 1 · 0⤊ 0⤋