anyone smart enough to show me how to do this math?

0 ⤊

anyone smart enough to show me how to do this math?

2i^2 - 3i + 4i^3 / 2i^5 - 3i - 2i^2

2007-09-04 14:58:39 · 3 answers · asked by argentina_mandy20 1 in Science & Mathematics ➔ Mathematics

3 answers

Evaluate the numerator (remember that i² = -1, i^3 = -i, and
i^4 = +1)
-2 - 3i -4i = -2 - 7i
Now do the denominator
2i - 3i + 2 = 2 -i (since i^5 = i)
then it's
(-2 -7i)/(2 - i)

HTH

Doug

2007-09-04 15:07:43 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋

i^2 = -1, i^3 = -i, i^4 = 1

so 2i^2 - 3i - 4i^3/(2i^5) - 3i-2i^2 = -6i + 4i/(2i) = 2 - 6i

2007-09-04 22:03:47 · answer #2 · answered by nyphdinmd 7 · 0⤊ 0⤋

8/23i>

answer

2007-09-04 22:03:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋