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Physics Help?

A spaceship travelled at a uniform velocity of 3.2 x 10^4 km/h for 2.7 days. What was the displacement of the spaceship?

2007-09-04 14:44:44 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics

1 answers

distance = speed x time

Time = 2.7 days x 24 hrs/day

distance = 3.2x10^4 km/hr x2.7 x 24 hrs = 2.07 x 10^6 km

2007-09-04 14:57:12 · answer #1 · answered by nyphdinmd 7 · 0⤊ 0⤋

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