Please help with this very simple pre-algebra/algebra question.11 points!?

Question

o.k
u have 8 moving boxes that you can use to pack up for college.
Each box can hold 15 lbs. of clothing and 60 lbs. of books. Let "c" be the number of boxes that contain clothing.


1.
write a function that gives the total pounds "T" of the boxes in terms of the number of boxes that contain clothing.

2. if 5 boxes contain clothing, how many lbs. will u be moving?
(for fun): )

i'll give you a best naswer and a thumbs up.

Answer 1

T = total weight
c = number clothing boxes
8-c = number of book boxes

so...

T = c(15) + (8-c)(60)
T = 15c + 480 - 60c
T = - 45c + 480

If 5 boxes contain clothing, this gives you

T = - 45 (5) + 480
T = -225 + 480
T = 255 lbs

Verify your answer by working the other way.

5 boxes @ 15 each is 75lbs.
If 5 boxes are clothes, the other 3 are books.
3 boxes @ 60 each is 180lbs.
Total weight is 75 + 180 = 255lbs

Answer 2

1. If c boxes contain clothes, 8-c boxes contain books. So the total weight is
T = 15(c) + 60(8-c)
= 15c + 480 - 60c
= 480 - 45c.

2. c = 5, so T = 480 - 45(5) = 255 lbs.

Answer 3

Umm, okay Carlos ---

1. 15c = T
Thought you only wanted the weight of boxes of clothes (?)

2. 5 (15) + 3 (60) = 75 + 180 = 255

Gee, actually, I'm not good at math.

Answer 4

Inflection factors are *available* the place f''(x)=0 or does no longer exist. And, i'm assuming you have a typo, so as that the 2d term is 19x², no longer 19x³. So: f'(x) = -42x² + 38x -a million f''(x) = -84x + 38. Then f''(x)=0 at the same time as x=38/eighty 4 = 19/forty 2. to make particular that this could be a authentic inflection ingredient, you may create a demonstration chart and coach that f''(x) > 0 for x<19/forty 2 and f''(x) < 0 for x>19/forty 2, and consequently that 19/forty 2 extremely represents a transformation in concavity of f (it rather is the definition of inflection ingredient). §

Answer 5

1. T= 480 - 45c
2. 705 lbs.

Answer 6

. I don't think you can give 11 Points for an Answer.
So there !