-6(2x-10)+12x
is it unsolvable or true?
2007-09-04 14:24:25 · 7 answers · asked by rickabamboo 3 in Science & Mathematics ➔ Mathematics
-6(2x-10)+12x<=180
-12x+60+12x<=180
60<=180
therefore true, because 60 is in fact less than 180.
2007-09-04 14:29:53 · answer #1 · answered by Anonymous · 0⤊ 1⤋
-6(2x-10) + 12 x <= 180
-12x +60 +12x <=180
60 <= 180
TRUE
Then, I guess that is it, unless this is a portion of a bigger problem.
By eliminating the x's, we have shown that this is true, whatever the value of x (i.e., it is always true; it is not a "conditional" inequality).
For example, set x = 3,217
-6(6,434 -10) + 38,604 <= 180
-38,604 +60 - 38,604 <= 180
60 <= 180
TRUE
Sometimes you are left with an x in the inequality and you would have to find the conditions (the values of x) for which the inequality is true.
But not in this case.
As soon as you have shown it to be true by eliminating the x's, you have shown it to be always true.
2007-09-04 21:34:52 · answer #2 · answered by Raymond 7 · 0⤊ 0⤋
That's right. You're left with a true statement (60 <= 180), so that means "all real values of x" is the solution, because no matter what value you plug in for x you always arrive back at this.
2007-09-04 21:30:39 · answer #3 · answered by Anonymous · 1⤊ 0⤋
-6(2x-10)+12x
-12x + 60 + 12x
60<180
Yep, this is right!
2007-09-04 21:31:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋
thats right.
60<180 is true, so the solution set is all real numbers
2007-09-04 21:28:55 · answer #5 · answered by bobo 3 · 1⤊ 0⤋
that is right... if you look carefully you'll see that your terms that include x will cancel each other out, therefore your statement will give us no information about the variable
2007-09-04 21:29:20 · answer #6 · answered by Anonymous · 0⤊ 0⤋
That is corret. There is nothing left to do Its true
2007-09-04 21:30:01 · answer #7 · answered by Up_In_Smoke 2 · 0⤊ 0⤋