How would you estimate the max height you could throw a ball vertically upward?

Question

And How would you estimate the max speed you could give it?

i'm learning about velocity and acceleration

thanks for answering

Answer 1

neglecting air resistance, you can find the maximum height reached by the ball by setting the velocity equal to zero.

use the kinematics equations.

step 1:

V = Vo + gt

where:
V = velocity at any time t
Vo = initial velocity
g = acceleration due to gravity, which has a value of -9.8m/s^2, (assuming the upward direction is positive)
t = time

Now, set V = 0. We have,

0 = Vo - 9.8(m/s^2)*t

We can then solve for the time it takes for the ball to reach the maximum height. That is,

t = Vo / 9.8(m/s^2) , for some value of Vo.

step 2:

use the value of t that we have just solved in step 1 to find the maximum height reached by the ball using the following equation:

Y = Yo + Vot + (1/2)gt^2

where:
Y = displacement (or height) of the ball any time t
Yo = initial displacement/height (if there's any)
Vo = initial velocity
g = -9.8 m/s^2
t = time

just plug-in the above equation the value of t for a given value of Vo in step 1 and you can find the maximum height reached by the ball and you're done.

bonus: if you want to find the time it took for the ball thrown in the air until it reached the ground, you can find that by multiplying the value of t in step 1 by 2. using symmetry principle.

there you have it. hope this helps. :-)

Answer 2

Physics? ball thrown upward vertically, optimal top? a ball is thrown upward with an preliminary velocity of 29.4 m/s. What optimal top does the ball attain? while an merchandise is thrown upward, it decelerates 9.8 m/s each 2d, till its velocity = 0 m/s. at present the article is at its optimal component. Then it speeds up downward at 9.8 m/s each 2d. If the commencing up component and end component are the comparable, the direction is symmetrical. the article strikes down the comparable distance it moved up. the main suitable velocity on the top of the downward trip equals the preliminary velocity of the upward trip. The time to realize the pass as much as the optimal component is the comparable because of the fact the time to fall backpedal to the commencing up component. the rate of a ball with preliminary vertical velocity of 29.4 m/s will shrink 9.8 m/s each 2d till the vertical velocity = 0 m/s vf = vi + a*t vf = 0 vi = 29.4 a = -9.8 0 = 29.4 +(-9.8 * t) t = 3 seconds because of the fact the rate is reducing at a relentless fee, the gap the ball strikes equals its widespread velocity situations the time. widespread velocity = (preliminary velocity + very final velocity) ÷ 2 widespread velocity = (+29.4 + 0) ÷ 2 = 14.7 m/s Time = 3 seconds Distance = 14.7 m/s * 3 s = 40 4.one million m is it 44m or 88 m (40 4) are you able to apply d=vt NO, because of the fact the rate replaced into no longer 29.4 m/s constantly!! v many times ability consistent velocity. while an merchandise is moving upward, its velocity is reducing because of the beautiful rigidity between the article and the earth. are you able to discover t? definite, via dividing the preliminary velocity via the deceleration

Answer 3

Measure the amount of time it is in the air. This is all you need to estimate the height and max speed.

Answer 4

hmmmmmmmmmm

ma

g is 9.8 m/s2