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Sums and differences of cubes??

Factor Completly:

1) 3z^5 - 3z^2

2) a^9 + b^12 c^15

2007-09-04 12:58:49 · 1 answers · asked by Aimee R 1 in Science & Mathematics Mathematics

1 answers

1) 3z^5-3z^2 = 3z^2(z^3-1) = 3z^2 (z^3-1^3) now use the formula for difference of cubes.
2) a^9+b^12c^15 = (a^3)^3 + (b^4c^5)^3 Now use sum of cubes formula.

2007-09-04 13:16:42 · answer #1 · answered by Snowflake 7 · 0 0

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