1, 0.1, 0.01, 0.001, ...
I shall re-write this as 1, 1/10, 1/100,..1/1000,...
(I did this only to clarify things a bit for me.)
This is a Geometric Progression common ratio 1/10
t(1)=1=10^0
t(2)=1/10=10^(-1)
t(3)=1/100=10^(-2)
t(n)=.....(10)^-(n-1)
t(n)= 10^(1-n)
Thus, t(3) would be 10^(1-2)=10^-2=1/100.
There, we did it right!
2007-09-04 11:02:18
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answer #1
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answered by Grampedo 7
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y = 1/(10^x)
is right, my answer is just the simplified version :)
2007-09-04 10:50:40
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answer #4
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answered by Anonymous
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