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4 answers

1, 0.1, 0.01, 0.001, ...
I shall re-write this as 1, 1/10, 1/100,..1/1000,...
(I did this only to clarify things a bit for me.)
This is a Geometric Progression common ratio 1/10
t(1)=1=10^0
t(2)=1/10=10^(-1)
t(3)=1/100=10^(-2)
t(n)=.....(10)^-(n-1)
t(n)= 10^(1-n)

Thus, t(3) would be 10^(1-2)=10^-2=1/100.
There, we did it right!

2007-09-04 11:02:18 · answer #1 · answered by Grampedo 7 · 0 0

Y = 10 ^-X

2007-09-04 10:45:51 · answer #2 · answered by heresmichelley 2 · 0 0

y = 1/10 power (n - 1) or 10 power (1-n)

2007-09-04 10:50:06 · answer #3 · answered by Beardo 7 · 0 0

y = 1/(10^x)

is right, my answer is just the simplified version :)

2007-09-04 10:50:40 · answer #4 · answered by Anonymous · 0 0

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