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1.(-2x^3)^3(4x^3)^-1
2.(x/10)^-1
3.(4y^-2)^3(4x^3)^-1

2007-09-04 09:24:20 · 1 answers · asked by Hobo L 1 in Science & Mathematics Mathematics

1 answers

1.(-2x^3)^3(4x^3)^-1
= -8x^9/4x^3 = -2x^6

2.(x/10)^-1 = 1/(x/10) = 10/x

3.(4y^-2)^3(4x^3)^-1
= 64y^-6 /4x^3
16/(x^3y^6)

2007-09-04 09:32:36 · answer #1 · answered by ironduke8159 7 · 0 0

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