You have th numbers 2, 4, 6, 8, and 10 to work with the come up with the answer of 0. You can use any order of operations and any grouping symbols. What's the answer?
2007-09-04 08:59:28 · 9 answers · asked by ♥ sk8rgal9000 ♥ 2 in Science & Mathematics ➔ Mathematics
use all of the numbers. only once.
2007-09-04 09:14:07 · update #1
(10+2-4-8)/6
2007-09-04 09:03:55 · answer #1 · answered by Pascal 7 · 1⤊ 1⤋
(-10+8-2+4)*6=0
2007-09-04 09:14:22 · answer #2 · answered by Anonymous · 1⤊ 1⤋
[(4 + 6) - 10][2 + 8]
[10 - 10][10]
0 x 10 = 0
2007-09-04 09:11:08 · answer #3 · answered by lenpol7 7 · 0⤊ 0⤋
[(6+4)-(8+2)]*10 = 0
2007-09-04 09:05:19 · answer #4 · answered by miggitymaggz 5 · 0⤊ 0⤋
(2 x 4) + 8 - 6 - 10
2007-09-04 09:04:41 · answer #5 · answered by John V 6 · 1⤊ 2⤋
8+2-10=0
2007-09-04 09:02:54 · answer #6 · answered by bedbye 6 · 0⤊ 4⤋
And you have to use all the numbers, right? Here you go:
((6+4) - (8+2)) * 10, or
(10 - 6 - 4) * (8+2), or
(10 - 6 - 4) * (8-2), etc.
2007-09-04 09:04:37 · answer #7 · answered by Anonymous · 1⤊ 1⤋
One way to think about this problem is to think about operations that always give you zero. For example, 0 times any number is 0. So if you can use a subset of numbers to get zero (6-4-2), for example, then just keep multiplying this (0) by all the other numbers.
Best of luck,
Catherine
2007-09-04 09:09:55 · answer #8 · answered by Catherine W 4 · 0⤊ 0⤋
Seriously, can i use negitives? I'll see if i can without negitives
[(8-6+4)-2/]10
[(-2 +4)-2]/10
[2-2]/10
0/10
0
Yea! I did it!
2007-09-04 09:13:51 · answer #9 · answered by Crazygirl ♥ aka GT 6 · 1⤊ 0⤋