a physics problem?

Question

An electron has a constant acceleration of +2.2 m/s2. At a certain instant its velocity is +8.8 m/s. What is its velocity (a) 2.4 s earlier and (b) 2.4 s later?

I have no clue what's the difference between 2.4s earlier and 2.4s later

Answer 1

Let V=at

V= 8.8 m/s at time t
a) V(t -2.4)=a(t - 2.4)=?
b) V(t +2.4)=a(t +2.4)=?

Ah...sorry
t= V/a=8.8/2.2= 4 sec

then
a) V(t -2.4)=a(t - 2.4)=2.2(4-2.4)=3.52 m/s
b) V(t +2.4)=a(t + 2.4)=2.2(4+2.4)=14.08 m/s