how would i solve this?
2007-09-04 08:23:59 · 10 answers · asked by qt123 1 in Science & Mathematics ➔ Mathematics
I believe the answer is 4>x, but I'm a little rusty.
Steps:
1. Cross-multiply so that 2(x+6)>5(x)
2. Simplify and subtract 2x from both sides:
2x+12>5x
-2x -2x
Equals: 12>3x
4. Divide both sides by 3 to simplify again, which leaves 4>x.
2007-09-04 08:38:17 · answer #1 · answered by misshiccups 3 · 1⤊ 3⤋
I would start by recognizing x= -6 and x= 0 would create an undefined number. That being said, if you follow the next few steps you will find that x < 4.
2(x+6) > 5x multiply both sides by divisors
2x + 12 > 5x multiply
12 > 3x subtract 2x from each side
4 > x divide both sides by 3
The final answer to this equation should read x = [-infinity,-6),(-6,0),(0,4).
2007-09-04 15:50:09 · answer #2 · answered by Mattyg 1 · 2⤊ 1⤋
Multiply both sides by x and by (x+6) giving you:
2(x+6) > x(5)
2x+12 > 5x
Now subtract 2x from both sides
12 > 3x
Lastly divide by 3
4 > x = X must be greater than 4
2007-09-04 15:32:55 · answer #3 · answered by drew2007 1 · 2⤊ 4⤋
2/x > 5/(x+6)
cross-multiplying
2(x+6) > 5x
2x+12 > 5x
12 > 5x-2x
12 > 3x
12/3 > x
4 > x
x < 4
x= {... -3, -2, -1, 0, 1, 2, 3}
:-):-)
2007-09-04 16:08:27 · answer #4 · answered by ? 2 · 0⤊ 2⤋
2/x > 5/(x+6)
Cross multiply, getting:
2(x+6) > 5x
2x+12 >5x
12> 3x
4>x, or x<4
2007-09-04 15:38:13 · answer #5 · answered by ironduke8159 7 · 0⤊ 4⤋
eliminate the denominators:
2x + 12 > 5x, or 12 > 3x. This is the same as
3x < 12, or x < 4.
X is less than 4
2007-09-04 15:35:06 · answer #6 · answered by John V 6 · 0⤊ 3⤋
2x+12>5x
2007-09-04 15:33:39
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answer #7
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answered by Anonymous
·
1⤊
1⤋
3x<12
x<4
- infinity
same denominator
2/x > 5/(x+6)
2/x - 5/(x+6) > 0
[2(x+6) -5x]/[x(x+6)] > 0
(2x+12-5x) / [x(x+6)] > 0
(12 - 3x) / [x(x+6)] > 0
(4 - x) / [x(x+6)] > 0
f(x) = (4 - x) / [x(x+6)]
x .................-infinity ........ -6 ........ 0 .......... 4 ........... + infinity
4-x ......................... +............ + ........ + ...... 0 ... - ..............
x ............................. - ............ - .... 0 ... + .......... + .............
x+6 ........................ - ....... 0 .... + ........ + .......... + ............
f(x) ......................... + ...... II .... - ... II ... + ... 0 .... - .............
] -infinity ; 0[ and ]0 ; 4[
2007-09-04 15:44:09 · answer #8 · answered by antone_fo 4 · 1⤊ 1⤋
2/x > 5/(X+6)---------------*x(x+6)
2(x+6)>5x
2x+12>5x
12>5x-2x
12>3x-------------divided by 3
4>x
x=]4,infinty[
2007-09-04 15:38:44 · answer #9 · answered by Anonymous · 0⤊ 2⤋
2/x 5/(x+6)
2(x+6) .....5x
2x + 12 .....5x
12 ......3x
4 .....x
solution: 5,6,7,8.....
2007-09-04 15:32:44 · answer #10 · answered by Indamo 7 · 1⤊ 3⤋