Solve this please : 3x^2+6x+2=0?

Question

solving just the problem

Answer 1

Quadratic formula

x = - b² ± √b² - 4ac / 2a

3x² + 6x + 2 - 0

Let

a = 3

b = 6

c = 2

x = - 6 ± √(6)² - 4(3)(2) / 2(3)

x = - 6 ± √36 - 24 / 6

x = - 6 ± √12 / 6

x = - 6 ± 3.464101615 / 6

- - - - - - - - - - -

Solving for +

x = - 6 + 3.464101615 / 6

x = - 2.535898385 / 6

x = - 0.422649731

- - - - - - - -

Solving for -

x = - 6 - 3.464101615 / 6

x = - 9.464101615 / 6

x = - 1.577350269

- - - - - - - -s-

Answer 2

Reorder the terms:
2 + 6x + 3x2 = 0

Begin completing the square. Divide all terms by
3 the coefficient of the squared term:

Divide each side by '3'.
0.6666666667 + 2x + x^2 = 0

Reorder the terms:
1 + 2x + x2 = -0.6666666667 + 1

Combine like terms: -0.6666666667 + 1 = 0.3333333333
1 + 2x + x2 = 0.3333333333

Factor a perfect square on the left side:
(x + 1)(x + 1) = 0.3333333333

Calculate the square root of the right side: 0.577350269

Break this problem into two subproblems by setting
(x + 1) equal to 0.577350269 and -0.577350269.

x + 1 = 0.577350269 or x + 1 = -0.577350269

The solution to the problem is based on the solutions

x = {-0.422649731, -1.577350269}

Answer 3

Using the quadratic formula the answer would be: -6 +/- sqrt3 / 3

Then you just solve sqrt3, divide by 3, then add/subtract from -6 to find your two answers for X.

Answer 4

3x^2+6x+2=0
x = ( - 6 +/- sqrt(6^2 - 4*2*3) ) / (2 * 3)
= ( - 6 +/- sqrt(36 - 24) ) / 6
= - 1 +/- sqrt(12) / 6
= - 1 +/- sqrt(4)sqrt(3) / 6
= - 1 +/- sqrt(3)/3.

Answer 5

are you tring to solve x or just the problem

Answer 6

Use the quadratic.

x = [-b (+-) sqrt(b^2 - 4ac)] / 2a

Answer 7

are you kidding me? ask me another question!