1. 2x - 5y = 0 (-2,0), (-10,6), (5,0)
2. 8x - 11y = 0
3. (-7,6) and (0,4); (-9, -3) and (1,5)
4. 4x + 3y = 4
5. The line passes through (-5,6) and is perpendicular to the line that has an x- intercept of 3 and a y- intercept of -9.
2007-09-04 07:54:20 · 3 answers · asked by love_militarymen 1 in Science & Mathematics ➔ Mathematics
for number 2 you have to find the gcf of 8 and 11, and that is 88. so you multiply 8 by 11 to get 88. then you multiply 11 by 8 to get 88. and 88 - 88 = 0. so x = 11 and y = 8. i really hope this helps you. and i hope you were looking for the variables value.
2007-09-04 08:37:39 · answer #1 · answered by ashley 3 · 0⤊ 0⤋
1. None of the ordered pairs satisfies the equation
2,3,4 Don,t understand what is wanted.
5. x/3+y/-9 = 1 is equation of line wiyh given intercepts.
Multiply by -9 getting : -3x +y = -9 or y= 3x-9 so slope = 3.
So slope line passing through (-5,6) must be -1/3
So its equation is y = -x/3 + b
6 = -(-5)/3+b so b = 6-5/3= 4 1/3 = 13/3
So equation is y= -x/3+13/3
In standard form this would be -x -3y +13 = 0
2007-09-04 15:12:19 · answer #2 · answered by ironduke8159 7 · 0⤊ 1⤋
It would help to clarify - I am a Chartered Mathematician but I don't understand what you are asking - what is your question???
2007-09-04 15:04:55 · answer #3 · answered by Sangmo 5 · 0⤊ 1⤋