I have 2 number.
A and B
A ~ B = 38
A ~ C = 59
N.B: ~ means difference.
what is B ~ C ?
How to calculate ?
How do i convince my result is correct ?
2007-09-04 06:32:09 · 4 answers · asked by calculus 1 in Science & Mathematics ➔ Mathematics
B-C
=(A-C)-(A-B)
=59-38=21
2007-09-04 06:39:13 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
A - B = 38 so that A = B + 38
A - C = 59 so that A = C + 59
Subtract the second eqn from the first:
(B + 38) - (C + 59) = A - A = 0
B - C = 59 - 38 = 21
2007-09-04 06:39:55 · answer #2 · answered by kellenraid 6 · 0⤊ 0⤋
A - B = 38 -> B = A - 38
A - C = 59 -> C = A - 59
B - C = A - 38 - (A - 59) = 21
2007-09-04 06:41:46 · answer #3 · answered by gebobs 6 · 0⤊ 0⤋
A~B =38 means B~A= ~ 38 then add the two equalities side by side, you get:
(B~A) +(A~C) = ~38 + 59, so B~A+A~C=B~C=21
2007-09-04 06:38:13 · answer #4 · answered by mohcis 2 · 0⤊ 0⤋