x^2 + 3x - 5/x^3 + 2x + h
In the problem I'm supposed to divide every term by x^3, but I don't know why. Can anyone help?
2007-09-04 06:15:10 · 5 answers · asked by super_nmaster2000 1 in Science & Mathematics ➔ Mathematics
You guys misunderstood the question. I want to know why specifically I have to divide by x^3.
2007-09-04 06:24:52 · update #1
Multiply the problem with 1/x^3
You get:
1/x^2 + 3/x^2 - 5/x^6 + 2/x^2 + h/x^3
2007-09-04 06:25:47 · answer #1 · answered by g2hn 3 · 0⤊ 0⤋
I think they want you to get a common denominator:
x^2 + 3x - 5/x^3 + 2x + h
= x^5/x^3+3x^4/x^3 - 5/x^3 +2x^4/x^3 +hx^3/x^3
= (x^5 + 5x^4 -5x^3 +hx^3)/x^3
But perhaps you meant(x^2+3x-5)/(x^3+2x +h).
If so, dividing every term by x^3 makes no sense.
Actually, either way, the division by X^3 is strange. See your teacher for an explanation. I would like to hear his/her answer.
2007-09-04 13:46:48 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
I have no idea why, other than to provide an exercise in
division of fractions by a fraction.
If you had meant the problem you've given to be
(x^2+3x-5) /(x^3+2x+h)' then
(x^2+3x-5)/(x^3+2x+h) /x^3=
(x^2+3x-5)/(x^6+2x^4+x^3h)
2007-09-04 13:38:31 · answer #3 · answered by Grampedo 7 · 0⤊ 0⤋
The purpose of dividing every term with x^3 is to get rid of the bottom denominator.
2007-09-04 13:23:04 · answer #4 · answered by BABALOO 3 · 0⤊ 0⤋
How would we know why? We can do it for you, but we can't tell you why you want to do it.
2007-09-04 13:18:34 · answer #5 · answered by gebobs 6 · 0⤊ 0⤋