college algebra question?

Question

1/2Y-11=1/6Y

Answer 1

(1/2) y - 11 = (1/6) y
3y - 66 = y
2y = 66
y = 33

Answer 2

There are six sets of answers, one for each interpretation of your question:

1. (1/2)Y - 11 = (1/6)Y

This gives Y=33

2. 1/(2Y) - 11 = 1/(6Y)

This gives Y=1/33

3. (1/2)Y - 11 = 1/(6Y)

This gives Y=11 plus or minus (2/3)root273

4. 1/(2Y) - 11 = (1/6)Y

This gives Y=-33 plus or minus 2root273

5. 1/(2Y - 11) = (1/6)Y

This gives Y= -1/2 or 6

6. 1/(2Y - 11) = 1/(6Y)

This gives Y=-11/4

Please write out your equations more accurately, there could easily be equations which have many different combinations of interpretations, which as you can see give very different solutions. Adding in a few brackets makes it much easier to understand. It does actually matter where the Y's are

Answer 3

1/2y - 11 = 1/6 y rearrange for y

1/2y - 1/6y = 11
y/2 - y/6 = 11
common denominator = 6
(3y - y) / 6 = 11
3y - y = 11 x 6 = 66
2y = 66
y = 66 / 2 = 33
y = 33

Answer 4

1/(2Y-11) = 1/(6Y)
2Y-11 = 6Y
-11 = 4Y
Y = -11/4
Y = -2 3/4

(1/2Y) - 11 = (1/6Y)
Multiply both sides by 6Y:
3 - 66Y = 1
2 = 66Y
Y = 1/33

Answer 5

1/2Y-11=1/6Y
multiply by 6 to get rid of fractions
6/2Y-66=6/6Y
3Y-66=Y
3Y-Y=66
2Y=66
Y=33

Answer 6

If you start by multiplying through by 6.

You get : 3y - 66 = y

Subtract y from both sides

2y - 66 = 0

Add 66 to both sides

2y = 66

Divide by 2

y = 33

There you go. Its simple when you know how!!!!

Answer 7

This is so easy I can't believe it's a college level question. Anyone with GCSE maths should be able to solve it.

Y/2 - 11 = Y/6

3Y/6 - 11 =Y/6

3Y/6 -Y/6 = 11

2Y/6 = 11

2Y = 66

Y = 33

Answer 8

y=33

Answer 9

1/2y-11=1/6y
1/2y-1/6y=11
3/6y-1/6y=11
2/6y=11
1/3y=11
33y=1
y=1/33