express the set of numbers x satisfying the given condition as an interval.
abs.(3x+5)<1
I put (-2,-4/3)
Is it correct? If so, how can I show work for it?
2007-09-04 05:58:45 · 3 answers · asked by Harmlessly Roaming 1 in Science & Mathematics ➔ Mathematics
| 3x + 5 | < 1
3x + 5 < 1
3x < - 4
x < - 4 / 3
3x + 5 > - 1
3x > - 6
x > - 2
- 2 < x < - 4 / 3
Interval is ( - 2 , - 4 / 3 )
2007-09-07 21:36:46 · answer #1 · answered by Como 7 · 1⤊ 0⤋
|3x+5| < 1 means
-(3x+5) < 1 < 3x+5
Take -3x-5 < 1 first, then
-3x < 6
x > -2
Now consider 1 < 3x+5, so
3x > -4
x> -4/3
But -2 < -4/3, so that x > -2 will get both of these. x > -2 is the answer
2007-09-04 06:06:44 · answer #2 · answered by kellenraid 6 · 0⤊ 0⤋
3x + 5 < 1
3x < -4
x < -4/3
3x + 5 > -1
3x > -6
x > -2
Looks right to me.
2007-09-04 06:04:14 · answer #3 · answered by gebobs 6 · 0⤊ 0⤋